[Co(NH_3)_6]^{3+} and [CoF_6]^{3-} are respec | vedclass

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(B) For $[Co(NH_3)_6]^{3+}$: The central metal ion is $Co^{3+}$ ($3d^6$ configuration). $NH_3$ is a strong field ligand,which causes pairing of electr

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Spin paired Complex,Spin free Complex

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(B) For $[Co(NH_3)_6]^{3+}$: The central metal ion is $Co^{3+}$ ($3d^6$ configuration). $NH_3$ is a strong field ligand,which causes pairing of electrons in the $d$-orbitals. This results in a $d^2sp^3$ hybridization,forming an inner orbital complex (spin-paired complex).For $[CoF_6]^{3-}$: The central metal ion is $Co^{3+}$ ($3d^6$ configuration). $F^-$ is a weak field ligand,which does not cause pairing of electrons. This results in an $sp^3d^2$ hybridization,forming an outer orbital complex (spin-free complex).Therefore,the correct sequence is spin-paired complex and spin-free complex.

List-$I$	List-$II$
$A. K_2[Ni(CN)_4]$	$I. sp^3$
$B. [Ni(CO)_4]$	$II. sp^3d^2$
$C. [Co(NH_3)_6]Cl_3$	$III. dsp^2$
$D. Na_3[CoF_6]$	$IV. d^2sp^3$

$[Co(NH_3)_6]^{3+}$ and $[CoF_6]^{3-}$ are respectively known as:

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Chromium hexacarbonyl,$Cr(CO)_6$,is an octahedral compound involving which type of hybridization?

The type of hybridization and the magnetic property of $[MnCl_6]^{3-}$ are $:$

Match List-$I$ with List-$II$:

List-$I$ List-$II$

$A. K_2[Ni(CN)_4]$ $I. sp^3$

$B. [Ni(CO)_4]$ $II. sp^3d^2$

$C. [Co(NH_3)_6]Cl_3$ $III. dsp^2$

$D. Na_3[CoF_6]$ $IV. d^2sp^3$

Choose the correct answer from the options given below:

$A$ complex involving $dsp^2$ hybridization has:

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