$A$ satellite of mass $m$ is orbiting the Earth (of radius $R$) at a height equal to the radius of the Earth. The total energy of the satellite in terms of $g$ (acceleration due to gravity on Earth's surface) is

$A$ satellite is revolving around the Earth with orbital speed $v_0$. If it stops suddenly,the speed with which it will strike the surface of the Earth would be: ($v_e =$ escape velocity of a particle on the Earth's surface)

Initially, a satellite of $100 \ kg$ is in a circular orbit of radius $1.5 R_E$. This satellite can be moved to a circular orbit of radius $3 R_E$ by supplying $\alpha \times 10^6 \ J$ of energy. The value of $\alpha$ is . . . . . . .
(Take Radius of Earth $R_E = 6 \times 10^6 \ m$ and $g = 10 \ m/s^2$)

Two satellites $A$ and $B$,having a ratio of masses $3 : 1$,are in circular orbits of radius $r$ and $4r$ respectively. Calculate the ratio of the total mechanical energy of $A$ and $B$.

If $R$ is the radius of orbit of a satellite,then the kinetic energy of the satellite is

Binding energy of a revolving satellite at height $h$ is $3.5 \times 10^{8} \,J$. Its potential energy is