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(C) The pressure inside a soap bubble is given by $P = P_0 + \frac{4T}{R}$,where $P_0$ is the atmospheric pressure,$T$ is the surface tension,and $R$

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(C) The pressure inside a soap bubble is given by $P = P_0 + \frac{4T}{R}$,where $P_0$ is the atmospheric pressure,$T$ is the surface tension,and $R$ is the radius of the bubble.The pressure at a depth $Z_0$ below the free surface of water is given by $P = P_0 + ho g Z_0$.Equating the two expressions for pressure:$P_0 + ho g Z_0 = P_0 + \frac{4T}{R}$This simplifies to:$ho g Z_0 = \frac{4T}{R}$Substituting the given values ($T = 2.5 	imes 10^{-2} \ N/m$,$R = 1 \ mm = 10^{-3} \ m$,$ho = 10^3 \ kg/m^3$,$g = 10 \ m/s^2$):$Z_0 = \frac{4 	imes 2.5 	imes 10^{-2}}{10^3 	imes 10 	imes 10^{-3}}$$Z_0 = \frac{10 	imes 10^{-2}}{10^1} = 10^{-2} \ m$$Z_0 = 1 \ cm$.

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