CuSO_{4(s)} + 5 H_2O_{(ell)} rightarrow CuSO_ | vedclass

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Question

(B) The given reaction is $CuSO_{4(s)} + 5 H_2O_{(\ell)} \rightarrow CuSO_4 \cdot 5 H_2O_{(s)}$.This reaction represents the addition of a specific nu

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Enthalpy of hydration of copper $(II)$ sulphate

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(B) The given reaction is $CuSO_{4(s)} + 5 H_2O_{(\ell)} \rightarrow CuSO_4 \cdot 5 H_2O_{(s)}$.This reaction represents the addition of a specific number of water molecules to an anhydrous salt to form its hydrated form.By definition,the enthalpy change associated with the addition of a specific number of water molecules to one mole of an anhydrous salt is known as the enthalpy of hydration.Therefore,the value of $\Delta H$ represents the enthalpy of hydration of copper $(II)$ sulphate.

$CuSO_{4(s)} + 5 H_2O_{(\ell)} \rightarrow CuSO_4 \cdot 5 H_2O_{(s)} ; \Delta H = -x \ kJ$. The value of $\Delta H$ represents:

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