2,2-dichloropropane stackrel{Aq. KOH}{longrig | vedclass

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Question

(C) Step $1$: Reaction of $2,2-$dichloropropane with aqueous $KOH$ gives a gem-diol intermediate,which loses a water molecule to form acetone $(CH_3CO

Vedclass · Accepted Answer

propane

Vedclass · Answer

(C) Step $1$: Reaction of $2,2-$dichloropropane with aqueous $KOH$ gives a gem-diol intermediate,which loses a water molecule to form acetone $(CH_3COCH_3)$ as product $A$.Step $2$: Clemmensen reduction of acetone $(CH_3COCH_3)$ using $Zn(Hg)/HCl$ reduces the carbonyl group to a methylene group $(-CH_2-)$,yielding propane $(CH_3CH_2CH_3)$ as product $B$.Therefore,the correct option is $C$.

$2,2-$dichloropropane $\stackrel{Aq. KOH}{\longrightarrow} A$ $\xrightarrow{\text{Clemmensen reduction}} B$. $B$ is

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