A buffer solution is prepared by mixing 0.01 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The concentration of $H^{+}$ ions in an acidic buffer can be calculated using the Henderson-Hasselbalch equation: $[H^{+}] = K_{a} 	imes \frac{[A

Vedclass · Accepted Answer

$3.3 	imes 10^{-10} \ M$

Vedclass · Answer

(B) The concentration of $H^{+}$ ions in an acidic buffer can be calculated using the Henderson-Hasselbalch equation: $[H^{+}] = K_{a} 	imes \frac{[Acid]}{[Salt]}$ Given: $K_{a} = 6.6 	imes 10^{-10}$ $[Acid] = [HCN] = 0.01 \ M$ $[Salt] = [NaCN] = 0.02 \ M$ Substituting the values: $[H^{+}] = (6.6 	imes 10^{-10}) 	imes \frac{0.01}{0.02}$ $[H^{+}] = (6.6 	imes 10^{-10}) 	imes 0.5$ $[H^{+}] = 3.3 	imes 10^{-10} \ M$

$A$ buffer solution is prepared by mixing $0.01 \ M$ $HCN$ and $0.02 \ M$ $NaCN$. If $K_{a}$ for $HCN$ is $6.6 \times 10^{-10}$,what is the concentration of $H^{+}$ ions in the solution?

Similar Questions

Which one of the following is not a buffer solution?

The $[HCO_{3}^{-}]/[H_{2}CO_{3}]$ ratio in the buffer present in blood $(pH = 7.4)$ is approximately $(pK_{a} = 6.1$ for $H_{2}CO_{3})$.

Which of the following is a buffer solution?

Which of the following is not a buffer solution?

$20 \ mL$ of $0.1 \ M \ H_2SO_4$ is added to $30 \ mL$ of $0.2 \ M \ NH_4OH$ solution. The $pH$ of the resultant mixture is [$pK_b$ of $NH_4OH = 4.7$].

Vedclass Test Series

Exam Paper Generator

Online Exam Module