A certain reaction occurs in two steps as:(i) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) An intermediate is a substance that is produced in one step of a reaction mechanism and consumed in a subsequent step.Adding the two steps:$(i)$ $

Vedclass · Accepted Answer

$NO_{(g)}$ is intermediate

Vedclass · Answer

(B) An intermediate is a substance that is produced in one step of a reaction mechanism and consumed in a subsequent step.Adding the two steps:$(i)$ $2 SO_{2(g)} + 2 NO_{2(g)} \rightarrow 2 SO_{3(g)} + 2 NO_{(g)}$$(ii)$ $2 NO_{(g)} + O_{2(g)} \rightarrow 2 NO_{2(g)}$Overall reaction: $2 SO_{2(g)} + O_{2(g)} \rightarrow 2 SO_{3(g)}$Here,$NO_{(g)}$ is produced in step $(i)$ and consumed in step $(ii)$,so it is an intermediate.

Label	Carbocation
$1$	$CH_3-CH^+-CH_3$
$2$	$CH_3^+$
$3$	$(CH_3)_3C^+$
$4$	$CH_3-CH_2^+$

$A$ certain reaction occurs in two steps as:
$(i)$ $2 SO_{2(g)} + 2 NO_{2(g)} \rightarrow 2 SO_{3(g)} + 2 NO_{(g)}$
$(ii)$ $2 NO_{(g)} + O_{2(g)} \rightarrow 2 NO_{2(g)}$
In the reaction,

Similar Questions

Which free radical from the following is least stable?

Arrange the following carbocations in the increasing order of stability with respect to their labels:
Label Carbocation
$1$ $CH_3-CH^+-CH_3$
$2$ $CH_3^+$
$3$ $(CH_3)_3C^+$
$4$ $CH_3-CH_2^+$

The orbital picture of a triplet carbene can be drawn as

The correct order of stability of the given carbocations is:

Which of the following carbocations will be most stable?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ certain reaction occurs in two steps as:$(i)$ $2 SO_{2(g)} + 2 NO_{2(g)} \rightarrow 2 SO_{3(g)} + 2 NO_{(g)}$$(ii)$ $2 NO_{(g)} + O_{2(g)} \rightarrow 2 NO_{2(g)}$In the reaction,