A gaseous mixture of O_2 and CH_4 are in the | vedclass

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(C) Let the mass of $O_2$ be $1x$ and the mass of $CH_4$ be $4x$.Number of moles of $O_2$ $(n_{O_2})$ = $\frac{	ext{mass}}{	ext{molar mass}} = \frac

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$1: 8$

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(C) Let the mass of $O_2$ be $1x$ and the mass of $CH_4$ be $4x$.Number of moles of $O_2$ $(n_{O_2})$ = $\frac{	ext{mass}}{	ext{molar mass}} = \frac{1x}{32}$.Number of moles of $CH_4$ $(n_{CH_4})$ = $\frac{	ext{mass}}{	ext{molar mass}} = \frac{4x}{16} = \frac{x}{4}$.The ratio of molecules is equal to the ratio of moles.Ratio = $n_{O_2} : n_{CH_4} = \frac{x}{32} : \frac{x}{4} = \frac{1}{32} : \frac{1}{4} = 1 : 8$.

$A$ gaseous mixture of $O_2$ and $CH_4$ are in the ratio $1: 4$ by mass. Find the ratio of their molecules.

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