In a sample of CaCO_3,there are 3.01 times 10 | vedclass

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(B) The dissociation reaction is $CaCO_3 	o Ca^{+2} + CO_3^{-2}$.Thus,$1$ molecule of $CaCO_3$ consists of one $Ca^{+2}$ ion and one $CO_3^{-2}$ ion.

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(B) The dissociation reaction is $CaCO_3 	o Ca^{+2} + CO_3^{-2}$.Thus,$1$ molecule of $CaCO_3$ consists of one $Ca^{+2}$ ion and one $CO_3^{-2}$ ion.Given $3.01 	imes 10^{23}$ ions of $Ca^{+2}$ and $CO_3^{-2}$ each,the number of $CaCO_3$ molecules is $3.01 	imes 10^{23}$.Since $6.022 	imes 10^{23}$ molecules = $1$ mole of $CaCO_3$,$3.01 	imes 10^{23}$ molecules = $0.5$ moles of $CaCO_3$.The molar mass of $CaCO_3$ is $40 + 12 + (3 	imes 16) = 100 \ g/mol$.Mass = $	ext{moles} 	imes 	ext{molar mass} = 0.5 \ mol 	imes 100 \ g/mol = 50 \ g$.

In a sample of $CaCO_3$,there are $3.01 \times 10^{23}$ ions of $Ca^{+2}$ and an equal number of $CO_3^{-2}$ ions. The mass of the sample is = $......$ grams.

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