The weight of 1 times 10^{22} molecules of Cu | vedclass

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(D) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $63.5 + 32 + (4 	imes 16) + 5 	imes (2 + 16) = 63.5 + 32 + 64 + 90 = 249.5 \ g/mol$. $6

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(D) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $63.5 + 32 + (4 	imes 16) + 5 	imes (2 + 16) = 63.5 + 32 + 64 + 90 = 249.5 \ g/mol$. $6.022 	imes 10^{23}$ molecules of $CuSO_4 \cdot 5H_2O$ weigh $249.5 \ g$. Therefore,the weight of $1 	imes 10^{22}$ molecules is: $	ext{Weight} = \frac{249.5 	imes 1 	imes 10^{22}}{6.022 	imes 10^{23}} \ g$. $	ext{Weight} = \frac{249.5}{60.22} \ g \approx 4.143 \ g$. Since $4.143 \ g$ is not exactly $4.159 \ g$,the correct option is $D$.

The weight of $1 \times 10^{22}$ molecules of $CuSO_4 \cdot 5H_2O$ is ........... $g$.

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