The mass of 4.48 dm^3 of a certain gas is 5. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) At $STP$,$1 \ mole$ of an ideal gas occupies $22.4 \ dm^3$ volume.Given volume of gas = $4.48 \ dm^3$.Number of moles $(n)$ = $\frac{	ext{Given V

Vedclass · Accepted Answer

$N_2$

Vedclass · Answer

(C) At $STP$,$1 \ mole$ of an ideal gas occupies $22.4 \ dm^3$ volume.Given volume of gas = $4.48 \ dm^3$.Number of moles $(n)$ = $\frac{	ext{Given Volume}}{	ext{Molar Volume at STP}} = \frac{4.48 \ dm^3}{22.4 \ dm^3/mol} = 0.2 \ mol$.We know that $n = \frac{	ext{Mass}}{	ext{Molar Mass (M)}}$.$0.2 \ mol = \frac{5.6 \ g}{M}$.$M = \frac{5.6 \ g}{0.2 \ mol} = 28 \ g/mol$.The molar mass of $N_2$ is $2 	imes 14 = 28 \ g/mol$.Therefore,the gas is $N_2$.

The mass of $4.48 \ dm^3$ of a certain gas is $5.6 \ g$ at $STP$. Assuming ideal behaviour,identify the probable gas from the following.

Similar Questions

Which of the following has the smallest number of molecules?

The number of atoms present in a drop of water weighing $1.8 \ g$ is.....

Which of the following contains the maximum number of atoms?

$1 \, \text{mol}$ of $CH_4$ contains

The number of gram molecules of chlorine in $6.02 \times 10^{25}$ hydrogen chloride molecules is

Vedclass Test Series

Exam Paper Generator

Online Exam Module