The expression $\frac{1}{\sqrt{5 + 4x}}$ can be expanded by the binomial theorem,if

For $n, p \in N-\{1\}$,the coefficient of $x^3$ in $\frac{(1-x)^{-1 / p}}{(1-x)^n}$ is:

The first negative coefficient in the terms occurring in the expansion of $(1+x)^{\frac{21}{5}}$ is

If $\frac{(1 - 3x)^{1/2} + (1 - x)^{5/3}}{\sqrt{4 - x}}$ is approximately equal to $a + bx$ for small values of $x$,then $(a,b) = $

If $x$ is numerically so small that $x^2$ and higher powers of $x$ can be neglected, then $\left(1+\frac{2x}{3}\right)^{3/2} \cdot (32+5x)^{-1/5}$ is approximately equal to

The coefficient of $x^3$ in the expansion of $(1-x)^{3/2}$,$(|x| < 1)$ is