A fair coin is tossed 4 times. If X is a rand | vedclass

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(D) coin is tossed $4$ times. The total number of outcomes is $n(S) = 2^4 = 16$. Let $X$ be the number of heads. The possible values for $X$ are $0, 1

Vedclass · Accepted Answer

$\frac{11}{16}$

Vedclass · Answer

(D) coin is tossed $4$ times. The total number of outcomes is $n(S) = 2^4 = 16$. Let $X$ be the number of heads. The possible values for $X$ are $0, 1, 2, 3, 4$. We need to find $P[X The number of ways to get $r$ heads in $n$ tosses is given by $\binom{n}{r}$. For $X=0$: $\binom{4}{0} = 1$ way. For $X=1$: $\binom{4}{1} = 4$ ways. For $X=2$: $\binom{4}{2} = \frac{4 	imes 3}{2 	imes 1} = 6$ ways. Total favorable outcomes = $1 + 4 + 6 = 11$. Therefore,$P[X < 3] = \frac{11}{16}$.

$A$ fair coin is tossed $4$ times. If $X$ is a random variable which indicates the number of heads,then $P[X < 3] = $

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