$A$ random variable $X$ has the following probability distribution:
$X$ $0$ $1$ $2$ $3$ $4$ $5$ $6$ $P(X)$ $k$ $3k$ $5k$ $7k$ $9k$ $11k$ $13k$
Then find $P(X \ge 2)$.
| $X$ | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ |
|---|---|---|---|---|---|---|---|
| $P(X)$ | $k$ | $3k$ | $5k$ | $7k$ | $9k$ | $11k$ | $13k$ |
Then find $P(X \ge 2)$.
- A$\frac{45}{49}$
- B$\frac{15}{49}$
- C$\frac{1}{49}$
- D$\frac{40}{49}$
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