A metal ball of mass 2 ,kg moving with a spee | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$(A)$ According to the law of conservation of momentum, the total momentum before the collision equals the total momentum after the collision.
$m_1 u

Vedclass · Accepted Answer

$60$

Vedclass · Answer

$(A)$ According to the law of conservation of momentum, the total momentum before the collision equals the total momentum after the collision.
$m_1 u_1 + m_2 u_2 = (m_1 + m_2)v$
Given $m_1 = 2 \,kg$, $u_1 = 10 \,ms^{-1}$, $m_2 = 3 \,kg$, and $u_2 = 0 \,ms^{-1}$.
$2 	imes 10 + 3 	imes 0 = (2 + 3)v$
$20 = 5v \implies v = 4 \,ms^{-1}$.
Initial kinetic energy $(K_i)$ = $\frac{1}{2} m_1 u_1^2 = \frac{1}{2} 	imes 2 	imes (10)^2 = 100 \,J$.
Final kinetic energy $(K_f)$ = $\frac{1}{2} (m_1 + m_2) v^2 = \frac{1}{2} 	imes (2 + 3) 	imes (4)^2 = \frac{1}{2} 	imes 5 	imes 16 = 40 \,J$.
Loss in kinetic energy = $K_i - K_f = 100 \,J - 40 \,J = 60 \,J$.

$A$ metal ball of mass $2 \,kg$ moving with a speed of $10 \,ms^{-1}$ has a head-on collision with a stationary ball of mass $3 \,kg$. If after the collision, both the balls move together, then the loss in kinetic energy due to the collision is: (in $\,J.$)

Similar Questions

Two particles of equal mass $m$ have respective initial velocities $u\hat{i}$ and $u\left(\frac{\hat{i}+ \hat{j}}{2}\right)$. They collide completely inelastically. The energy lost in the process is

$A$ particle of mass $m$ moves with velocity $v$ towards the East. It collides with another particle of the same mass and same speed moving towards the North and sticks to it. What will be the velocity of the combined particles?

$A$ metal ball of mass $2 \,kg$ moving with a velocity of $36 \,km/h$ has a head-on collision with a stationary ball of mass $3 \,kg$. If after the collision,the two balls move together,the loss in kinetic energy due to the collision is ........ $J$.

$A$ body of mass $2 \, kg$ is moving with velocity $10 \, m/s$ towards the east. Another body of the same mass and same velocity moving towards the north collides with the former,coalesces,and moves towards the north-east. What is its final velocity?

$A$ particle of mass $m$ moving towards west with speed $v$ collides with another particle of mass $m$ moving towards south. If the two particles stick to each other,the speed of the new particle of mass $2m$ will be ..........

Vedclass Test Series

Exam Paper Generator

Online Exam Module