$A$ galvanometer of resistance $G$ is shunted by a resistance of $5 \Omega$. To keep the main current in the circuit unchanged,the resistance to be put in series with the same galvanometer is

  • A
    $\frac{G^2}{5+G}$
  • B
    $\frac{5 G}{5+G}$
  • C
    $\frac{G}{5+G}$
  • D
    $\frac{5^2}{5+G}$

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