A galvanometer of resistance 100 Omega requir | vedclass

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(B) Given: Resistance of galvanometer $G = 100 \Omega$, Shunt resistance $S = 1 \Omega$, Full-scale deflection current $I_g = 10 \mu A = 10 	imes 10^

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$1.01$

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(B) Given: Resistance of galvanometer $G = 100 \Omega$, Shunt resistance $S = 1 \Omega$, Full-scale deflection current $I_g = 10 \mu A = 10 	imes 10^{-6} A$. To convert a galvanometer into an ammeter, the shunt resistance $S$ is connected in parallel. The total current $I$ required for full-scale deflection is given by the formula: $I = I_g \left( \frac{G+S}{S} ight)$. Substituting the values: $I = 10 \mu A \left( \frac{100 + 1}{1} ight)$. $I = 10 \mu A 	imes 101 = 1010 \mu A$. Converting to milliamperes: $I = 1.01 	ext{ mA}$.

$A$ galvanometer of resistance $100 \Omega$ requires $10 \mu A$ current for full-scale deflection. If a shunt resistance of $1 \Omega$ is connected in parallel to convert it into an ammeter, what is the minimum current required to obtain full-scale deflection (in $\text{ mA}$)?

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