$A$ voltmeter of range $3 \, V$ and resistance $200 \, \Omega$ cannot be converted to an ammeter of range

$A$ galvanometer of resistance $10 \Omega$ changes its range from $1 \text{ mA}$ to $101 \text{ mA}$ when a resistive wire is connected in parallel. If the resistivity of the material of the wire and its area of cross-section are $1 \times 10^{-6} \Omega \text{ m}$ and $1 \text{ mm}^2$ respectively,then the length of the wire is (in $cm$)

$A$ galvanometer has a resistance of $80 \Omega$ and it is shunted with a resistance of $20 \Omega$. If $20 \%$ of the main current flows through the galvanometer, what is the value of the main current (in $\text{ A}$)?

The range of a voltmeter of resistance $G \ \Omega$ is $V$ volt. The resistance required to be connected in series with it in order to convert it into a voltmeter of range $nV$ volt, will be

An ammeter of resistance $20 \Omega$ gives full scale deflection when $1 \text{ mA}$ current flows through it. What is the maximum current that can be measured by connecting $4$ resistors each of $16 \Omega$ in parallel with the meter (in $\text{ mA}$)?

What is the value of shunt resistance required to convert a galvanometer of resistance $ 100 \Omega $ into an ammeter of range $ 1 \text{ A} $? Given: Full scale deflection of the galvanometer is $ 5 \text{ mA} $.