A copper ring having a cut such as not to for | vedclass

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(A) When a bar magnet is dropped through a complete conducting ring,an induced current flows in the ring due to the change in magnetic flux,which crea

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$g$

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(A) When a bar magnet is dropped through a complete conducting ring,an induced current flows in the ring due to the change in magnetic flux,which creates a repulsive force (Lenz's Law) that opposes the motion of the magnet,resulting in an acceleration less than $g$.However,in this case,the copper ring has a cut,meaning it does not form a complete loop. Therefore,no induced current can flow through the ring.Since there is no induced current,there is no magnetic force (repulsive or attractive) acting on the magnet to oppose its motion.Consequently,the only force acting on the falling magnet is gravity.Thus,the acceleration of the falling magnet remains equal to $g$.

$A$ copper ring having a cut such as not to form a complete loop is held horizontally and a bar magnet is dropped through the ring with its length along the axis of the ring as shown in figure. The acceleration of the falling magnet is ($g=$ acceleration due to gravity)

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