$A$ circular coil of wire consisting of $100$ turns each of radius $9 \ cm$ carries a current of $0.4 \ A$. The magnitude of the magnetic field at the centre of the coil is $[\mu_0 = 12.56 \times 10^{-7} \text{ SI Units}]$.
- A$2.4 \times 10^{-11} \ T$
- B$2.79 \times 10^{-5} \ T$
- C$2.79 \times 10^{-4} \ T$
- D$2.79 \times 10^{-3} \ T$
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Similar Questions
Two identical circular current loops of radius $R$ carrying equal currents $I$ are placed such that their axes are inclined at $45^\circ$ to each other. The distance from the center of each loop to point $P$ is $\sqrt{3}R$. The resultant magnetic field at $P$ is:
DifficultKCET 2026
View SolutionFor the given circuits,the magnetic field at point $O$ is given. Which of the following is correct?
$(i)$ $(ii)$ $(iii)$ $(A). \frac{\mu_0 i}{r} \otimes$ $(A). \frac{\mu_0 i}{4}(\frac{1}{r_1} - \frac{1}{r_2}) \otimes$ $(A). \frac{\mu_0 i}{4}(\frac{1}{r_1} - \frac{1}{r_2}) \otimes$ $(B). \frac{\mu_0 i}{2r} \odot$ $(B). \frac{\mu_0 i}{4}(\frac{1}{r_1} + \frac{1}{r_2}) \otimes$ $(B). \frac{\mu_0 i}{4}(\frac{1}{r_1} + \frac{1}{r_2}) \otimes$ $(C). \frac{\mu_0 i}{4r} \otimes$ $(C). \frac{\mu_0 i}{4}(\frac{1}{r_1} - \frac{1}{r_2}) \odot$ $(C). \frac{\mu_0 i}{4}(\frac{1}{r_1} - \frac{1}{r_2}) \odot$ $(D). \frac{\mu_0 i}{4r} \odot$ $(D). 0$ $(D). 0$
| $(i)$ | $(ii)$ | $(iii)$ |
| $(A). \frac{\mu_0 i}{r} \otimes$ | $(A). \frac{\mu_0 i}{4}(\frac{1}{r_1} - \frac{1}{r_2}) \otimes$ | $(A). \frac{\mu_0 i}{4}(\frac{1}{r_1} - \frac{1}{r_2}) \otimes$ |
| $(B). \frac{\mu_0 i}{2r} \odot$ | $(B). \frac{\mu_0 i}{4}(\frac{1}{r_1} + \frac{1}{r_2}) \otimes$ | $(B). \frac{\mu_0 i}{4}(\frac{1}{r_1} + \frac{1}{r_2}) \otimes$ |
| $(C). \frac{\mu_0 i}{4r} \otimes$ | $(C). \frac{\mu_0 i}{4}(\frac{1}{r_1} - \frac{1}{r_2}) \odot$ | $(C). \frac{\mu_0 i}{4}(\frac{1}{r_1} - \frac{1}{r_2}) \odot$ |
| $(D). \frac{\mu_0 i}{4r} \odot$ | $(D). 0$ | $(D). 0$ |
Difficult
View SolutionMagnetic field $dB$ due to a current element at any point on its axis is . . . . . . .
$A$ current passing through a circular coil of two turns produces a magnetic field $B$ at its centre. The coil is then rewound so as to have four turns and the same current is passed through it. The magnetic field at its centre now is
DifficultMHT CET 2011
View Solution$A$ straight wire of diameter $0.5\, mm$ carrying a current of $1\, A$ is replaced by another wire of $1\, mm$ diameter carrying the same current. The strength of the magnetic field at a point far away is
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