A straight wire of diameter 0.5, mm carrying | vedclass

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(D) The magnetic field $B$ at a distance $r$ from a long straight current-carrying wire is given by the formula $B = \frac{\mu_0}{4\pi} \frac{2i}{r}$.

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(D) The magnetic field $B$ at a distance $r$ from a long straight current-carrying wire is given by the formula $B = \frac{\mu_0}{4\pi} \frac{2i}{r}$.Here,$\mu_0$ is the permeability of free space,$i$ is the current flowing through the wire,and $r$ is the perpendicular distance from the wire.As per the formula,the magnetic field $B$ depends only on the current $i$ and the distance $r$ from the wire.It is independent of the radius or diameter of the wire.Since the current $i$ remains the same and the distance $r$ is considered far away (implying the same observation point),the magnetic field strength remains unchanged.

$A$ straight wire of diameter $0.5\, mm$ carrying a current of $1\, A$ is replaced by another wire of $1\, mm$ diameter carrying the same current. The strength of the magnetic field at a point far away is

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