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(B) The Reynolds number $(R_{n})$ for the flow of a fluid through a pipe is given by the formula:$R_{n} = \frac{v_{c} \rho d}{\eta}$Where:$v_{c}$ is t

Vedclass · Accepted Answer

$0.125$

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(B) The Reynolds number $(R_{n})$ for the flow of a fluid through a pipe is given by the formula:$R_{n} = \frac{v_{c} ho d}{\eta}$Where:$v_{c}$ is the critical velocity,$ho$ is the density of the fluid $(10^3 \,kg/m^3)$,$d$ is the diameter of the tube $(2 	imes r = 2 	imes 1 \,cm = 2 	imes 10^{-2} \,m)$,$\eta$ is the coefficient of viscosity $(1 	imes 10^{-3} \,Ns/m^2)$,$R_{n}$ is the critical Reynolds number $(2500)$.Rearranging the formula to solve for $v_{c}$:$v_{c} = \frac{R_{n} \eta}{ho d}$Substituting the given values:$v_{c} = \frac{2500 	imes 10^{-3}}{10^3 	imes 2 	imes 10^{-2}}$$v_{c} = \frac{2.5}{20} = 0.125 \,m/s$Thus, the speed of flow required to convert the streamline flow into turbulent flow is $0.125 \,m/s$.

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