$A$ thin metal wire of length $L$ and mass $M$ is bent to form a semicircular ring as shown. The moment of inertia about the axis $XX^1$ passing through its ends is:

  • A
    $\frac{M L^2}{4 \pi^2}$
  • B
    $\frac{2 ML^2}{\pi^2}$
  • C
    $\frac{M L^2}{2 \pi^2}$
  • D
    $\frac{ML^2}{\pi^2}$

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