A transistor is used as a common emitter ampl | vedclass

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(B) The correct option is $B$.Concept: The current gain $\beta$ is given by $\beta = \frac{\Delta I_C}{\Delta I_B}$.Given: $\Delta I_C = 1.5 \ mA = 1.

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$1000$

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(B) The correct option is $B$.Concept: The current gain $\beta$ is given by $\beta = \frac{\Delta I_C}{\Delta I_B}$.Given: $\Delta I_C = 1.5 \ mA = 1.5 	imes 10^{-3} \ A$ and $\Delta I_B = 20 \ \mu A = 20 	imes 10^{-6} \ A$.Calculating $\beta$: $\beta = \frac{1.5 	imes 10^{-3}}{20 	imes 10^{-6}} = \frac{1500}{20} = 75$.The voltage gain $A_v$ is given by $A_v = \beta 	imes \frac{R_L}{R_i}$.Given: Load resistance $R_L = 2 \ k\Omega = 2000 \ \Omega$ and input resistance $R_i = 150 \ \Omega$.Substituting the values: $A_v = 75 	imes \frac{2000}{150} = 75 	imes \frac{40}{3} = 25 	imes 40 = 1000$.

$A$ transistor is used as a common emitter amplifier with a load resistance $2 \ k\Omega$. The input resistance is $150 \ \Omega$. The base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is

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