$A$ transistor having $\alpha=0.8$ is connected in a common-emitter configuration. When the base current changes by $6 \text{ mA}$, the change in collector current is: (in $\text{ mA}$)

$A$ common emitter transistor amplifier is connected with a load resistance of $6 k\Omega$. When a small a.c. signal of $15 mV$ is added to the base-emitter voltage, the alternating base current is $20 \mu A$ and the alternating collector current is $1.8 mA$. What is the voltage gain of the amplifier?

Assertion : In a common emitter transistor amplifier,the input current is much less than the output current.
Reason : The common emitter transistor amplifier has very high input impedance.

The current amplification factor and the collector current in a $CE$ transistor circuit are $100$ and $2.2 \text{ mA}$ respectively. Then the base current is (in $\mu A$)

In a transistor circuit,the emitter-base circuit of a $n-p-n$ transistor is always

$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. What is the change in collector current?