$A$ light wave of wavelength $\lambda$ is incident on a slit of width $d$. The resulting diffraction pattern is observed on a screen at a distance $D$. If the linear width of the principal maxima is equal to the width of the slit,then the distance $D$ is:

  • A
    $\frac{d}{\lambda}$
  • B
    $\frac{2 \lambda}{d}$
  • C
    $\frac{d^{2}}{2 \lambda}$
  • D
    $\frac{2 \lambda^{2}}{d}$

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Visible light of wavelength $6000 \times 10^{-8} \; cm$ falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at $60^{\circ}$ from the central maximum. If the first minimum is produced at $\theta_{1}$,then $\theta_{1}$ is close to.....$^{\circ}$

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