$A$ ray of light is incident at the polarising angle $\theta$ on an air-glass interface. If $\lambda_{a}$ and $\lambda_{g}$ are the wavelengths of light in air and glass respectively,then:

$A$ solid glass sphere of refractive index $n=\sqrt{3}$ and radius $R$ contains a spherical air cavity of radius $\frac{R}{2}$,as shown in the figure. $A$ very thin glass layer is present at the point $O$ so that the air cavity (refractive index $n=1$) remains inside the glass sphere. An unpolarized,unidirectional and monochromatic light source $S$ emits a light ray from a point inside the glass sphere towards the periphery of the glass sphere. If the light is reflected from the point $O$ and is fully polarized,then the angle of incidence at the inner surface of the glass sphere is $\theta$. The value of $\sin \theta$ is

Light is incident at an angle $i$ on a glass slab. The reflected ray is completely polarised. The angle of refraction is

Unpolarised light is incident on the boundary between two dielectric media,whose dielectric constants are $2.8$ (medium $1$) and $6.8$ (medium $2$),respectively. To satisfy the condition that the reflected and refracted rays are perpendicular to each other,the angle of incidence should be $\tan ^{-1}\left(1+\frac{10}{\theta}\right)^{\frac{1}{2}}$. The value of $\theta$ is $.............$ (Given for dielectric media,$\mu_{r}=1$)

The Brewster angle for air to glass transition of light is (Refractive index of glass $= 1.5$).

The angle of incidence at which reflected light is completely polarized for reflection from air to a medium of refractive index $n$ is: