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(D) According to Brewster's Law,the refractive index $\mu$ is given by $\mu = 	an i_p$,where $i_p$ is the polarizing angle.Given $\mu = 1.73$ and $

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$30$

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(D) According to Brewster's Law,the refractive index $\mu$ is given by $\mu = 	an i_p$,where $i_p$ is the polarizing angle.Given $\mu = 1.73$ and $	an 60^{\circ} = 1.73$,we have $	an i_p = 	an 60^{\circ}$,which implies $i_p = 60^{\circ}$.When light is incident at the polarizing angle,the reflected ray and the refracted ray are perpendicular to each other,meaning $i_p + r = 90^{\circ}$.Substituting the value of $i_p$,we get $60^{\circ} + r = 90^{\circ}$.Therefore,the angle of refraction $r = 90^{\circ} - 60^{\circ} = 30^{\circ}$.

$A$ ray of unpolarised light is incident on a glass surface of refractive index $1.73$ at the polarizing angle. The angle of refraction will be. [Take $\tan 60^{\circ} = 1.73$] (in $^{\circ}$)

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