Light is incident on a glass surface at a polarizing angle of $57.5^{\circ}$. Then the angle between the reflected ray and the refracted ray is: (in $^{\circ}$)

$A$ solid glass sphere of refractive index $n=\sqrt{3}$ and radius $R$ contains a spherical air cavity of radius $\frac{R}{2}$,as shown in the figure. $A$ very thin glass layer is present at the point $O$ so that the air cavity (refractive index $n=1$) remains inside the glass sphere. An unpolarized,unidirectional and monochromatic light source $S$ emits a light ray from a point inside the glass sphere towards the periphery of the glass sphere. If the light is reflected from the point $O$ and is fully polarized,then the angle of incidence at the inner surface of the glass sphere is $\theta$. The value of $\sin \theta$ is

What is the Brewster angle for air to glass transition (in $^{\circ}$)? (Refractive index of glass $= 1.5.)$

The angle of incidence at which reflected light is completely polarized for reflection from air to a medium of refractive index $n$ is:

Unpolarised red light is incident on the surface of a lake at an incident angle $\theta_{R}$. An observer seeing the light reflected from the water surface through a polariser notices that on rotating the polariser,the intensity of light drops to zero at a certain orientation. The red light is replaced by unpolarised blue light. The observer sees the same effect with reflected blue light at an incident angle $\theta_{B}$. Then,

The angle of polarisation for a medium with respect to air is $60^{\circ}$. The critical angle of this medium with respect to air is