The angle of polarisation for a medium with respect to air is $60^{\circ}$. The critical angle of this medium with respect to air is

  • A
    $\sin ^{-1} \sqrt{3}$
  • B
    $\tan ^{-1} \sqrt{3}$
  • C
    $\cos ^{-1} \sqrt{3}$
  • D
    $\sin ^{-1} \frac{1}{\sqrt{3}}$

Explore More

Similar Questions

Unpolarised light is incident from air on a plane surface of a material of refractive index $\mu$. At a particular angle of incidence $i$,it is found that the reflected and refracted rays are perpendicular to each other. Which of the following options is correct for this situation?

$A$ ray of light is incident at a polarising angle such that its deviation is $24^{\circ}$. Then the angle of incidence is: (in $^{\circ}$)

For a given medium, the polarizing angle is $60^o$. What will be the critical angle for this medium?

The polarising angle of a transparent medium is $\theta$. Let the speed of light in the medium be $v$. Then the relation between $\theta$ and $v$ is [where $c$ is the velocity of light in air].

The refractive index of a medium is $\sqrt{3}$. If unpolarised light is incident on it at the polarizing angle of the medium,then the angle of refraction is......$^o$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo