A stretched string fixed at both ends has m n | vedclass

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(A) For a stretched string fixed at both ends,the length $l$ is given by $l = \frac{p \lambda}{2}$,where $p$ is the number of loops (or segments). In

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$(m-1) \frac{\lambda}{2}$

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(A) For a stretched string fixed at both ends,the length $l$ is given by $l = \frac{p \lambda}{2}$,where $p$ is the number of loops (or segments). In a standing wave on a string fixed at both ends,the number of loops $p$ is equal to the number of anti-nodes. The relationship between the number of nodes $m$ and the number of anti-nodes $p$ is given by $m = p + 1$. Therefore,the number of loops is $p = m - 1$. Substituting this value of $p$ into the length formula,we get $l = \frac{(m-1) \lambda}{2}$.

$A$ stretched string fixed at both ends has $m$ nodes,then the length of the string will be

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