A gardener pushes a lawn roller through a dis | vedclass

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(D) The work done $W$ by a constant force $F$ is given by the formula: $W = F \cdot S \cdot \cos(	heta)$, where $S$ is the displacement and $	heta$

Vedclass · Accepted Answer

$2940$

Vedclass · Answer

(D) The work done $W$ by a constant force $F$ is given by the formula: $W = F \cdot S \cdot \cos(	heta)$, where $S$ is the displacement and $	heta$ is the angle between the force and the displacement.Given:Force $F = 30 \,kg-wt = 30 	imes 9.8 \,N = 294 \,N$Displacement $S = 20 \,m$Angle $	heta = 60^{\circ}$Substituting these values into the formula:$W = 294 	imes 20 	imes \cos(60^{\circ})$Since $\cos(60^{\circ}) = 0.5$, we get:$W = 294 	imes 20 	imes 0.5$$W = 294 	imes 10 = 2940 \,J$Therefore, the work done by the gardener is $2940 \,J$.

$A$ gardener pushes a lawn roller through a distance of $20 \,m$. If he applies a force of $30 \,kg-wt$ in a direction inclined at $60^{\circ}$ to the ground, the work done by the gardener in pushing the roller is (Given: $g=9.8 \,m/s^2$) (in $\,J$)

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