C_6H_5OC_2H_5 + HI rightarrow X + Y. Here X a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of an alkyl aryl ether with $HI$ involves the cleavage of the $C_{alkyl}-O$ bond because the $C_{aryl}-O$ bond has partial double bon

Vedclass · Accepted Answer

$C_6H_5OH$ and $C_2H_5I$

Vedclass · Answer

(A) The reaction of an alkyl aryl ether with $HI$ involves the cleavage of the $C_{alkyl}-O$ bond because the $C_{aryl}-O$ bond has partial double bond character due to resonance and is stronger.Therefore,the reaction proceeds as follows:$C_6H_5-O-C_2H_5 + HI \rightarrow C_6H_5OH + C_2H_5I$Here,$X$ is $C_6H_5OH$ (phenol) and $Y$ is $C_2H_5I$ (ethyl iodide).Thus,the correct option is $A$.

$C_6H_5OC_2H_5 + HI \rightarrow X + Y$. Here $X$ and $Y$ are . . . . . . .

Similar Questions

The major product of the above reaction is:

Identify the product $(A)$ of the following reaction:
$C_2H_5-O-C_2H_5 + CO \xrightarrow[500 \text{ atm}]{BF_3 / 150^{\circ}C} A$

On the treatment of the following compound with a strong acid,the most susceptible site for bond cleavage is

The products formed when diethyl ether is reacted with cold $HI$ are

In the given reaction
$C_6H_5 - O - CH_2 - CH_3 \xrightarrow{\text{Excess } HI / \Delta} [X] + [Y]$
$[X]$ and $[Y]$ will respectively be

Vedclass Test Series

Exam Paper Generator

Online Exam Module