frac{d}{dx}(sin(x^2) + cos(x^2)) = . . . . | vedclass

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(A) To find the derivative of $f(x) = \sin(x^2) + \cos(x^2)$,we use the chain rule.Let $u = x^2$,then $\frac{du}{dx} = 2x$.The derivative is given by

Vedclass · Accepted Answer

$2x(\cos(x^2) - \sin(x^2))$

Vedclass · Answer

(A) To find the derivative of $f(x) = \sin(x^2) + \cos(x^2)$,we use the chain rule.Let $u = x^2$,then $\frac{du}{dx} = 2x$.The derivative is given by $\frac{d}{dx}(\sin(u) + \cos(u)) = \frac{d}{du}(\sin(u) + \cos(u)) \cdot \frac{du}{dx}$.$= (\cos(u) - \sin(u)) \cdot 2x$.Substituting $u = x^2$ back into the expression,we get:$= 2x(\cos(x^2) - \sin(x^2))$.Thus,the correct option is $A$.

$\frac{d}{dx}(\sin(x^2) + \cos(x^2)) = $ . . . . . .

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