$A$ coil of self-inductance $0.5 \ mH$ carries a current of $2 \ A$. The energy stored in Joule is . . . . . . .

Energy in a current carrying coil is stored in the form of

When a current $I$ flows through a coil,it stores the energy $E_1$ in it. Now the current is reduced to $I/2$,the energy stored in the coil becomes $E_2$. The change in the energy is

The expression for the magnetic energy stored in a solenoid of length $L$, in terms of magnetic field $B$ and area $A$ is

$A$ $100 mH$ coil carries a current of $1 A$. Energy stored in the form of magnetic field is (in $J$)

In an inductor of inductance $L = 100 \, mH$,a current of $I = 10 \, A$ is flowing. The energy stored in the inductor is ....... $J$.