The expression for the magnetic energy stored in a solenoid of length $L$, in terms of magnetic field $B$ and area $A$ is

$A$ solenoid of inductance $2 \ H$ carries a current of $1 \ A$. What is the magnetic energy stored in the solenoid (in $J$)?

If the current through an inductor increases from $2 \ A$ to $3 \ A$,the magnetic energy stored in the inductor increases by: (in $\%$)

The magnetic potential energy stored in a certain inductor is $25\, mJ,$ when the current in the inductor is $60\, mA.$ This inductor is of inductance ......$H$.

$A$ coil of self-inductance $0.5 \ mH$ carries a current of $2 \ A$. The energy stored in Joule is . . . . . . .

Assertion : If the current in a solenoid is reversed in direction while keeping the same magnitude,the magnetic field energy stored in the solenoid remains unchanged.
Reason : Magnetic field energy density is proportional to the magnetic field.