$A$ galvanometer of resistance $240 \Omega$ allows only $4 \%$ of the main current to pass through it after connecting a shunt resistance. The value of the shunt resistance is (in $\Omega$)

In a circuit for finding the resistance of a galvanometer by the half-deflection method,a $6\,V$ battery and a high resistance of $11\,k\Omega$ are used. The figure of merit of the galvanometer is $60\,\mu A/\text{division}$. In the absence of shunt resistance,the galvanometer produces a deflection of $\theta = 9$ divisions when current flows in the circuit. The value of the shunt resistance that can cause the deflection of $\theta/2$ is closest to .................. $\Omega$.

The resistance of a galvanometer coil is $R$. What is the shunt resistance required to convert it into an ammeter of range $4$ times?

$A$ current of $200 \ \mu A$ deflects the coil of a moving coil galvanometer through $60^{\circ}$. The current required to cause a deflection of $\frac{\pi}{10}$ radians is: (in $\mu A$)

$A$ galvanometer of resistance $100 \Omega$ requires $10 \mu A$ current for full-scale deflection. If a shunt resistance of $1 \Omega$ is connected in parallel to convert it into an ammeter, what is the minimum current required to obtain full-scale deflection (in $\text{ mA}$)?

$A$ galvanometer of resistance $G$ can be converted into a voltmeter of range $V$ by connecting a resistance $R$ in series with it. The series resistance required to change its range to $\frac{V}{3}$ is