p rightarrow sim q can also be written as | vedclass

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(B) We know that the implication $A \rightarrow B$ is logically equivalent to $\sim A \vee B$.Applying this rule to $p \rightarrow \sim q$,we get:$p \

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$\sim p \vee \sim q$

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(B) We know that the implication $A \rightarrow B$ is logically equivalent to $\sim A \vee B$.Applying this rule to $p \rightarrow \sim q$,we get:$p \rightarrow \sim q \equiv \sim p \vee \sim q$.This can also be verified using the truth table:| $p$ | $q$ | $\sim p$ | $\sim q$ | $p \rightarrow \sim q$ | $\sim p \vee \sim q$ ||---|---|---|---|---|---|| $T$ | $T$ | $F$ | $F$ | $F$ | $F$ || $T$ | $F$ | $F$ | $T$ | $T$ | $T$ || $F$ | $T$ | $T$ | $F$ | $T$ | $T$ || $F$ | $F$ | $T$ | $T$ | $T$ | $T$ |Since the truth values of $p \rightarrow \sim q$ and $\sim p \vee \sim q$ are identical for all possible truth values of $p$ and $q$,they are logically equivalent.

$p \rightarrow \sim q$ can also be written as

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