A linear object of height 10 text{ cm} is kep | vedclass

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(B) Given: Height of object $h = 10 	ext{ cm}$,radius of curvature $R = 15 	ext{ cm}$,object distance $u = -10 	ext{ cm}$.Focal length $f = R/2 = 1

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magnified and inverted

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(B) Given: Height of object $h = 10 	ext{ cm}$,radius of curvature $R = 15 	ext{ cm}$,object distance $u = -10 	ext{ cm}$.Focal length $f = R/2 = 15/2 = 7.5 	ext{ cm}$. For a concave mirror,$f = -7.5 	ext{ cm}$.Since the object is placed at $u = -10 	ext{ cm}$,and the focal length is $f = -7.5 	ext{ cm}$,the object is placed between the focus $(F)$ and the centre of curvature $(C)$ because $f When an object is placed between $F$ and $C$ in front of a concave mirror,the image formed is real,inverted,and magnified.

$A$ linear object of height $10 \text{ cm}$ is kept in front of a concave mirror of radius of curvature $15 \text{ cm}$,at a distance of $10 \text{ cm}$. The image formed is

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