A microscope has an objective of focal length | vedclass

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(B) Given: Focal length of objective,$f_{o} = 1 \ cm$; Focal length of eyepiece,$f_{e} = 6 \ cm$; Tube length,$L = 30 \ cm$; Least distance of distinc

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(B) Given: Focal length of objective,$f_{o} = 1 \ cm$; Focal length of eyepiece,$f_{e} = 6 \ cm$; Tube length,$L = 30 \ cm$; Least distance of distinct vision,$D = 25 \ cm$. For a compound microscope,the magnifying power $M$ when the final image is formed at the near point $(D)$ is given by: $M = \frac{L}{f_{o}} \left(1 + \frac{D}{f_{e}}ight)$ Substituting the given values: $M = \frac{30}{1} \left(1 + \frac{25}{6}ight)$ $M = 30 \left(\frac{6 + 25}{6}ight)$ $M = 30 \left(\frac{31}{6}ight)$ $M = 5 	imes 31 = 155$. Rounding to the nearest provided option,the magnification is approximately $150$.

$A$ microscope has an objective of focal length $1 \ cm$ and an eyepiece of focal length $6 \ cm$. If the tube length is $30 \ cm$ and the image is formed at the least distance of distinct vision,what is the magnification produced by the microscope? Take $D = 25 \ cm$.

Similar Questions

$A$ compound microscope consists of an objective lens of focal length $2.0 \, cm$ and an eyepiece of focal length $6.25 \, cm$ separated by a distance of $15 \, cm$. What is the magnifying power when the final image is formed at the least distance of distinct vision $(25 \, cm)$?

The image formed by the objective lens of a compound microscope is:

In a microscope, the objective has a focal length $f_0 = 2 \ cm$ and the eyepiece has a focal length $f_e = 4 \ cm$. The tube length is $32 \ cm$. The magnification produced by this microscope for normal adjustment is . . . . . . .

In a compound microscope,the objective lens and eyepiece have focal lengths of $0.95 \ cm$ and $5 \ cm$ respectively,and are kept at a distance of $20 \ cm$. The final image is formed at a distance of $25 \ cm$ from the eyepiece. Calculate the magnifying power.

Magnification of a compound microscope is $30$. The focal length of the eyepiece is $5 \, cm$ and the image is formed at the near point (distance of distinct vision) of $25 \, cm$. The magnification of the objective lens is:

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