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(B) For a compound microscope, the magnification $m$ in normal adjustment is given by the formula:$m = \left( \frac{L}{f_0} ight) 	imes \left( \fra

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$100$

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(B) For a compound microscope, the magnification $m$ in normal adjustment is given by the formula:$m = \left( \frac{L}{f_0} ight) 	imes \left( \frac{D}{f_e} ight)$Where $L$ is the tube length, $f_0$ is the focal length of the objective, $f_e$ is the focal length of the eyepiece, and $D$ is the least distance of distinct vision $(D = 25 \ cm)$.Given: $L = 32 \ cm$, $f_0 = 2 \ cm$, $f_e = 4 \ cm$, $D = 25 \ cm$.Substituting the values:$m = \left( \frac{32}{2} ight) 	imes \left( \frac{25}{4} ight)$$m = 16 	imes 6.25$$m = 100$

In a microscope, the objective has a focal length $f_0 = 2 \ cm$ and the eyepiece has a focal length $f_e = 4 \ cm$. The tube length is $32 \ cm$. The magnification produced by this microscope for normal adjustment is . . . . . . .

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