A step-down transformer has 50 turns on the s | vedclass

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(B) Given: Number of turns on secondary,$N_{s} = 50$; Number of turns on primary,$N_{p} = 1000$; Primary voltage,$V_{p} = 220 \ V$; Primary current,$I

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$20 \ A$

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(B) Given: Number of turns on secondary,$N_{s} = 50$; Number of turns on primary,$N_{p} = 1000$; Primary voltage,$V_{p} = 220 \ V$; Primary current,$I_{p} = 1 \ A$. We know the transformer ratio formula: $\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}$. Using the relation $\frac{N_{s}}{N_{p}} = \frac{I_{p}}{I_{s}}$,we can find the output current $I_{s}$ as: $I_{s} = \frac{N_{p}}{N_{s}} 	imes I_{p}$. Substituting the given values: $I_{s} = \frac{1000}{50} 	imes 1$. $I_{s} = 20 	imes 1 = 20 \ A$. Thus,the output current of the transformer is $20 \ A$.

$A$ step-down transformer has $50$ turns on the secondary and $1000$ turns on the primary winding. If the transformer is connected to a $220 \ V, 1 \ A$ $A$.$C$. source,what is the output current of the transformer?

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