$A$ mixture of phenol and aniline shows negative deviation from Raoult's law. This is due to the formation of

  • A
    polar covalent bond
  • B
    non-polar covalent bond
  • C
    intermolecular hydrogen bond
  • D
    intramolecular hydrogen bond

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Similar Questions

In a mixture of $A$ and $B$ components,the solution shows negative deviation when:

$A$ liquid solution is formed by mixing $10 \, moles$ of aniline and $20 \, moles$ of phenol at a temperature where the vapour pressure of pure liquid aniline and phenol are $90 \, mmHg$ and $87 \, mmHg$ respectively. The possible vapour pressure of the solution at that temperature is ............. $mmHg$.

Vapour pressures of pure liquids $A$ and $B$ are $300$ and $800 \ torr$ respectively at $25^{\circ}C$. When these two liquids are mixed at this temperature to form a solution in which mole percentage of $B$ is $90$,the total vapour pressure is observed to be $720 \ torr$. Which of the following is true for this solution?

Which of the following statements is correct regarding a solution of two compounds $A$ and $B$ exhibiting positive deviation from ideal behaviour?

$A$ solution of acetone in ethanol:

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