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(A) For a solution to exhibit positive deviation from Raoult's law: $1$. The intermolecular attractive forces between $A-A$ and $B-B$ are stronger tha

Vedclass · Accepted Answer

Intermolecular attractive forces between $A-A$ and $B-B$ are stronger than those between $A-B$.

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(A) For a solution to exhibit positive deviation from Raoult's law: $1$. The intermolecular attractive forces between $A-A$ and $B-B$ are stronger than those between $A-B$. $2$. The enthalpy of mixing is positive,i.e.,$\Delta_{mix} H > 0$. $3$. The volume of mixing is positive,i.e.,$\Delta_{mix} V > 0$. Since options $A$,$B$,and $C$ are all correct descriptions of positive deviation,this question is a multiple-correct type. However,in standard single-choice contexts,the primary cause is the intermolecular force interaction.

Which of the following statements is correct regarding a solution of two compounds $A$ and $B$ exhibiting positive deviation from ideal behaviour?

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