Medium
$A$ colloidal solution is subjected to an electric field,and the colloidal particles move towards the anode. The amount of electrolytes $BaCl_{2}$,$AlCl_{3}$,and $NaCl$ required to coagulate the given colloid is in the order:
- A$NaCl > BaCl_{2} > AlCl_{3}$
- B$BaCl_{2} < AlCl_{3} > NaCl$
- C$AlCl_{3} = NaCl = BaCl_{2}$
- D$AlCl_{3} > BaCl_{2} > NaCl$
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View SolutionMatch List-$I$ with List-$II$.
List-$I$ (Colloid Preparation Method) List-$II$ (Chemical Reaction) $(a)$ Hydrolysis $(i) \; 2 AuCl_{3} + 3 HCHO + 3 H_{2}O \rightarrow 2 Au(sol) + 3 HCOOH + 6 HCl$ $(b)$ Reduction $(ii) \; As_{2}O_{3} + 3 H_{2}S \rightarrow As_{2}S_{3}(sol) + 3 H_{2}O$ $(c)$ Oxidation $(iii) \; SO_{2} + 2 H_{2}S \rightarrow 3 S(sol) + 2 H_{2}O$ $(d)$ Double Decomposition $(iv) \; FeCl_{3} + 3 H_{2}O \rightarrow Fe(OH)_{3}(sol) + 3 HCl$
Choose the most appropriate answer from the options given below.
| List-$I$ (Colloid Preparation Method) | List-$II$ (Chemical Reaction) |
| $(a)$ Hydrolysis | $(i) \; 2 AuCl_{3} + 3 HCHO + 3 H_{2}O \rightarrow 2 Au(sol) + 3 HCOOH + 6 HCl$ |
| $(b)$ Reduction | $(ii) \; As_{2}O_{3} + 3 H_{2}S \rightarrow As_{2}S_{3}(sol) + 3 H_{2}O$ |
| $(c)$ Oxidation | $(iii) \; SO_{2} + 2 H_{2}S \rightarrow 3 S(sol) + 2 H_{2}O$ |
| $(d)$ Double Decomposition | $(iv) \; FeCl_{3} + 3 H_{2}O \rightarrow Fe(OH)_{3}(sol) + 3 HCl$ |
Choose the most appropriate answer from the options given below.
DifficultJEE MAIN 2021
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