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(A) The work done by a system in a cyclic process is equal to the area enclosed by the $P-V$ diagram.For a clockwise cycle,the work done is positive,a

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$-750$

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(A) The work done by a system in a cyclic process is equal to the area enclosed by the $P-V$ diagram.For a clockwise cycle,the work done is positive,and for a counter-clockwise cycle,the work done is negative.In the given diagram,the cycle $A ightarrow B ightarrow C ightarrow A$ is counter-clockwise.Area of the triangle $ABC = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$.Base $= (V_C - V_B) = (10 - 5) \ m^3 = 5 \ m^3$.Height $= (P_A - P_B) = (400 - 100) \ N/m^2 = 300 \ N/m^2$.Area $= \frac{1}{2} 	imes 5 	imes 300 = 750 \ J$.Since the cycle is counter-clockwise,the work done by the system is $W = -750 \ J$.

$A$ thermodynamic system undergoes a cyclic process $ABC$ as shown in the diagram. The work done by the system per cycle is (in $J$)

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