(D) The initial radioactive substance is $_{88}^{228}X$. Each $\alpha$ emission decreases the atomic number by $2$ and the mass number by $4$. Each $\

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(D) The initial radioactive substance is $_{88}^{228}X$. Each $\alpha$ emission decreases the atomic number by $2$ and the mass number by $4$. Each $\beta$ emission increases the atomic number by $1$ and does not change the mass number. After emitting $3$ $\alpha$ and $3$ $\beta$ particles,the atomic number of $Y$ becomes: $88 - (3 \times 2) + (3 \times 1) = 88 - 6 + 3 = 85$. The element with atomic number $85$ is Astatine $(At)$,which belongs to group $VIIA$ (Halogens) of the periodic table.

Class 12 Chemistry Nuclear Chemistry Causes of radioactivity and Group displacement law

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$A$ radioactive substance $_{88}X^{228}$ $(IIA)$ emits $3$ $\alpha$ and $3$ $\beta$ particles to form $Y$. To which group of the long form of the periodic table does $Y$ belong?

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A
$IVA$
B
$VA$
C
$VIA$
D
$VIIA$

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Causes of radioactivity and Group displacement law

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$A$ radioactive substance $_{88}X^{228}$ $(IIA)$ emits $3$ $\alpha$ and $3$ $\beta$ particles to form $Y$. To which group of the long form of the periodic table does $Y$ belong?

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An isotope $_Y{A^X}$ undergoes a series of $m$ alpha and $n$ beta disintegrations to form a stable isotope $_{Y-10}{B^{X-32}}$. The values of $m$ and $n$ are respectively:

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