A T.V. tower has a height of 100 , m. The ave | vedclass

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(A) The range $d$ of a $T$.$V$. tower of height $h$ is given by $d = \sqrt{2Rh}$, where $R$ is the radius of the earth.Given $h = 100 \, m$ and $R = 6

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$4 	imes 10^6$

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(A) The range $d$ of a $T$.$V$. tower of height $h$ is given by $d = \sqrt{2Rh}$, where $R$ is the radius of the earth.Given $h = 100 \, m$ and $R = 6.37 	imes 10^6 \, m$.$d = \sqrt{2 	imes 6.37 	imes 10^6 	imes 100} = \sqrt{12.74 	imes 10^8} \approx 35.7 	imes 10^3 \, m = 35.7 \, km$.The area covered by the tower is $A = \pi d^2 = 3.14 	imes (35.7)^2 \approx 3.14 	imes 1274.49 \approx 4000 \, km^2$.The population covered is given by $	ext{Population} = 	ext{Area} 	imes 	ext{Population Density}$.$	ext{Population} = 4000 \, km^2 	imes 1000 \, km^{-2} = 4 	imes 10^6$.

$A$ $T$.$V$. tower has a height of $100 \, m$. The average population density around the tower is $1000 \, km^{-2}$ and the radius of the earth is $6.37 \times 10^6 \, m$. The population covered is

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