A TV tower has a height of 160 ,m. Its covera | vedclass

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(A) Given,height of the $TV$ tower,$h = 160 \,m$.Radius of the Earth,$R_e = 6400 \,km = 6.4 	imes 10^6 \,m$.The coverage range $(d)$ of a $TV$ tower

Vedclass · Accepted Answer

$45255 \,m$

Vedclass · Answer

(A) Given,height of the $TV$ tower,$h = 160 \,m$.Radius of the Earth,$R_e = 6400 \,km = 6.4 	imes 10^6 \,m$.The coverage range $(d)$ of a $TV$ tower is given by the formula:$d = \sqrt{2 R_e h}$.Substituting the values:$d = \sqrt{2 	imes 6.4 	imes 10^6 	imes 160}$.$d = \sqrt{2048 	imes 10^6}$.$d = \sqrt{20.48 	imes 10^8} \approx 45254.8 \,m$.Rounding off,we get $d \approx 45255 \,m$.

$A$ $TV$ tower has a height of $160 \,m$. Its coverage range is nearly (Earth's radius,$R_e = 6400 \,km$):

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