A signal of frequency 10 kHz and peak voltage | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given:Frequency of the modulating signal,$f_s = 10 kHz$.Carrier frequency,$f_c = 1 MHz = 1000 kHz$.In amplitude modulation,the side-band frequenci

Vedclass · Accepted Answer

$1010, 990$

Vedclass · Answer

(A) Given:Frequency of the modulating signal,$f_s = 10 kHz$.Carrier frequency,$f_c = 1 MHz = 1000 kHz$.In amplitude modulation,the side-band frequencies are given by the formula:$f_{side} = f_c \pm f_s$Substituting the values:Upper side-band frequency $(f_{USB})$ = $f_c + f_s = 1000 kHz + 10 kHz = 1010 kHz$.Lower side-band frequency $(f_{LSB})$ = $f_c - f_s = 1000 kHz - 10 kHz = 990 kHz$.Therefore,the side-band frequencies are $1010 kHz$ and $990 kHz$.

$A$ signal of frequency $10 kHz$ and peak voltage $10 V$ is used to amplitude modulate a carrier of frequency $1 MHz$ and peak voltage $20 V$. The side-band frequencies in $kHz$ are

Similar Questions

What is the minimum height of an antenna required to transmit a radio signal of frequency $20 \text{ MHz}$?

Consider telecommunication using optical fibers. Which of the following statements is $NOT$ true?

The frequency range for commercial $FM$ radio broadcasting is .......

Communication on ground is through electromagnetic waves of wavelength

Vedclass Test Series

Exam Paper Generator

Online Exam Module